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Release of power accumulator #4

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Old 05-17-2008, 11:18 PM
Jeff Jeff is offline
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Release of power accumulator #4
I would like to know when the release of power accumulator #4 is complete in a swinger's swing action.

From TGM, I understand that a triple barrel swing involves the release of power accumulators 4,2,3 in that sequence. At what point in the downswing has power accumulator #4 fully released?

Consider the following graph from a paper by Phil Cheetham of TPI.



Note that pelvic rotation peaks when the lead arm is parallel to the ground in the early downswing, and shoulder rotation peaks when the hands reach waist level. After that time point, one can say that the downswing pivot action starts subsiding, which apparently is causally responsible for the release of power accumulator #4. If that is the time point when power accumulator #4 starts to release, then when is release deemed to be complete?

Jeff.
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Old 05-18-2008, 01:06 AM
O.B.Left O.B.Left is offline
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Jeff

Keep it up. I love your questions, as the answers always bring some enlightenment to the rest of us seekers.

I think that the "in line" position for accum #4 is the left arm returning to 90 degrees to the shoulders at both arms straight. At this point, I believe, it stops, in that there is no further movement beyond 90 degrees.


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Last edited by O.B.Left : 05-18-2008 at 01:31 AM.
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Old 05-19-2008, 12:14 PM
Jeff Jeff is offline
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OB

Thanks for replying.

If the power accumulator #4 is fully released at the "both arms straight" end-followthrough position, then is it correct to state that all power accumulators used in a swinger's action are fully released at the same time time point, even though the release sequence is 4/2/3?

Secondly, you stated a 90 degree angle. However, I presume that the angle depends on the degree of shoulder openess at impact. The more open one rotates the shoulders by impact, the less the angle.

Consider the following sequence of Hogan's swing - note that left arm-shoulder angle is <90 degrees at impact, and that it remains at that angle well into the finish phase of the swing.



Jeff.
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Old 05-19-2008, 03:44 PM
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12 piece bucket 12 piece bucket is offline
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Originally Posted by Jeff View Post
OB

Thanks for replying.

If the power accumulator #4 is fully released at the "both arms straight" end-followthrough position, then is it correct to state that all power accumulators used in a swinger's action are fully released at the same time time point, even though the release sequence is 4/2/3?

Secondly, you stated a 90 degree angle. However, I presume that the angle depends on the degree of shoulder openess at impact. The more open one rotates the shoulders by impact, the less the angle.

Consider the following sequence of Hogan's swing - note that left arm-shoulder angle is <90 degrees at impact, and that it remains at that angle well into the finish phase of the swing.



Jeff.

Jeff . . . Good questions dude . . . It's simply the relationship of the arm and the shoulder joint. It doesn't matter really where the shoulder is "in space". Once the arm is directly under the shoulder it is "fully released." So you could have a stroke where you had no shoulder turn at all. Just simply #4 accumulator motion via the #1 accumulator (right elbow) and once it is 90 degrees it's released with the shoulder turn "zeroed out". The shoulder turn simply carries the #4 angle via turning into the #4 pressure point. So basically the arm moves up and down the chest. It can be driven by the shoulder turn or swinging the arm.

So in the 1st frame I would say that #4 is "fully released" in your sequence of Mr. Hogan above. #4 is considered the master accumulator because if the left arm doesn't move "down the chest" then none of the other accumulators can release. You'd swing literally over the top of the ball.

6-B-4-0 THE FORTH POWER ACCUMULATOR The angle formed by the Left Arm and Left Shoulder forms the Forth Power Accumulator. It is not only an independent Power Accumulator, but its Triggering function as the Checkrein of the Right Elbow is also vastly important and it thus can be the Accumulator of the Accumulators – or Master Accumulator. Also see 2-M-4.

As Accumulator #4 it is Pivot (Body) Power supplying the initial acceleration of the Downstroke to throw the Lever Assemblies toward Impact by the Thrust of the Shoulder Turn. See 7-13. Another major contribution to Impact Power is geometric – it is the first link in the Swing Radius power train between the Club and the Feet.

“Left Arm Power” in any form or amount can still be considered #4 Accumulator Action. Otherwise it actually substitutes for the Pivot to introduce the circular motion required to produce Centrifugal Force.

RADIUS POWER

6-B-4-A MAXIMUM POWER is obtained by using maximum On Plane Shoulder Turn Thrust against Pressure Point #4 per 7-19, and maximum Swing Radius (6-B-0).

6-B-4-B ZERO ACCUMULATION is either no Shoulder Turn or the use of Accumulator #1 alone for actuating the Primary Lever Assembly.

6-B-4-C MAXIMUM TRIGGER DELAY is achieved by using either the Standard or Delayed Pivot (to increase the Lag of the Downstroke Shoulder Turn) with a Snap Loading Action (per 7-19-3 and 10-22-C) followed by a Snap Release (10-24-E) with a Pitch


One fault people have (me for one) . . . is NOT RELEASING #4 down the chest rather "OUT" which basically moves the hands out away from the plane rather than keeping them "in on-plane." Thus a compensatory move must be made because the radius (left shoulder to clubhead to ball) has been disrupted a miriad of compensations have to be made to get the sweetspot on the ball (standing up, flip, alligator arms . . etc. etc.).

But back to the sequence you put up . . . I think the #4 angle releases differently for different plane angles and hand paths. In other words, Hogan's pivot and plane is going to have the left arm "pinned" via the pressure point longer than say a Jack Nicklaus or Scott Hoch. Some one with lots of #3 angle that swings on a "wider" arc of approach (or just arc) is going to have #4 pressure point "pinned" by the pivot due to the hand path requirements, pivot requirements . . . to stay ON THE SELECTED PLANE.
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Last edited by 12 piece bucket : 05-19-2008 at 04:13 PM.
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Old 05-19-2008, 05:15 PM
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Nice one, pards!
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Old 05-19-2008, 06:39 PM
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Originally Posted by okie View Post
Nice one, pards!
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Old 05-19-2008, 06:44 PM
golfbulldog golfbulldog is offline
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Originally Posted by 12 piece bucket View Post

One fault people have (me for one) . . . is NOT RELEASING #4 down the chest rather "OUT" which basically moves the hands out away from the plane rather than keeping them "in on-plane." Thus a compensatory move must be made because the radius (left shoulder to clubhead to ball) has been disrupted a miriad of compensations have to be made to get the sweetspot on the ball (standing up, flip, alligator arms . . etc. etc.).
I like your point about releasing acc.4 down...I think the whole "blast the left arm off your chest" can be a bit misleading.

I think that you blast it from above the nipple line to below the nipple line...



In this video I tried to show the stage where the pivot carries the power package to...then the acc 4 releases...and the right shoulder appears to stop rotating toward the target and goes down whilst the acc 4 releases...the left shoulder moves up quite alot as the axis tilt becomes more evident.

But the left arm moves almost independently after "blast down" of the left arm.
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Old 05-19-2008, 09:17 PM
Jeff Jeff is offline
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When one talks of blasting the left arm off the chest with the downswing pivot action thereby releasing power accumulator #4, doesn't the left arm have to move both downwards (towards the left foot) and outwards (towards the ball-target line), and isn't the direction of left arm movement determined by the movement of the conjoined hand unit, which is itself directionally moved by the right forearm/PP#3 which traces the straight plane line and also moves towards the aiming point?

Jeff.
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Old 05-19-2008, 09:38 PM
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Originally Posted by golfbulldog View Post
I like your point about releasing acc.4 down...I think the whole "blast the left arm off your chest" can be a bit misleading.

I think that you blast it from above the nipple line to below the nipple line...



In this video I tried to show the stage where the pivot carries the power package to...then the acc 4 releases...and the right shoulder appears to stop rotating toward the target and goes down whilst the acc 4 releases...the left shoulder moves up quite alot as the axis tilt becomes more evident.

But the left arm moves almost independently after "blast down" of the left arm.
Nice work . . . if you notice in the slow part . .. there are TWO components to the #4 accumulator motion . . . UP AND DOWN and BACK AND FORTH . . . they have to be sequenced properly just like the pivot inorder to have the hands stay IN AND ON PLANE . . . I think this is why Homer said that #4 was the master accumulator . . . a. because it must release inorder for the other accumulators to release AND b. because if you get too much down early the club get "stuck" behind you or if you get to much out early you hands are over the plane.

There is fo' sho' a big relation to HOW the pivot must work inorder for #4 to release to keep the hands on plane . . . Steep plane . . . more slidy pivot to keep the hands IN and not flying out over the plane early. Flat plane more rotation to get the club OUT and keep it from getting stuck and not getting to low point b/c the angle of attack is too shallow.

I had a nice conversation with Eddie Cox on this . . . #4 has to release DOWN your chest. Eddie said you need to feel like you are taking your sternum into your left bicept in a way that blasts the arm more DOWN and less out. If you blast the left arm OUT early the hands stay to HIGH and you have to do some weird stuff to get the club to shallow out (stand up, shrink your arms) otherwise you just bend the plane line left and become Craig Parry.
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Old 05-19-2008, 09:41 PM
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Originally Posted by Jeff View Post
When one talks of blasting the left arm off the chest with the downswing pivot action thereby releasing power accumulator #4, doesn't the left arm have to move both downwards (towards the left foot) and outwards (towards the ball-target line), and isn't the direction of left arm movement determined by the movement of the conjoined hand unit, which is itself directionally moved by the right forearm/PP#3 which traces the straight plane line and also moves towards the aiming point?

Jeff.
Jeff . . . I'd agree with you. The left arm is blasted kinda toward the left foot as well as out to the ball. Homer preferred a hand controlled pivot (procedure) for sure. BUT there's only so much the hands can do to overcome a faulty start down. If the pivot doesn't move precisely with the plane requirements, the hands get drug OVER or UNDER the plane and have to fight hard to recover . . . no matter how much "mind in the hands" or "monitoring #3" or "tracing" you do. You can only trace as good as your pivot allows you to trace.
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