Ok so what were have found out here is what accumulator 3 is from the vertical relationship that the left arm has with the inclined plane.
So how do we do that....
We firstly need to know where the left arm is on its circle relative to the plane that is vertical to the inclined plane (think angled hinging). We do this by referencing the vertical relationship with the ground and how many degrees has it moved around relative to that.
Now we need to find out exactly how to calculate the hinge action plane relative to that point - and it best to look at the 90 degree perspective here. The angle of the hinge action in relation to the ground and the angle of the inclined plane relative into the ground also plays a role here.
For example
Lets just look at an example with the inclined plane at 30 degrees and the left arm 90 degrees from low point relative to inclined plane
Hinge action----------Left arm Low Point-----Left Arm 90 degrees
Ok so you can see why the horizontal plane at 90 degrees is exactly the same as the inclined plane with the ground and the vertical plane is - 90 of that figure...
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