Pass the Grapes
 

Hey, you're the guy who 'couldn't help yourself.' [Post #16 (of 91!)]

So...Leave me out of this! :)

I'm perfectly at home watching the 'braintrust' work from the sidelines. Plus, Mathew clued me in before he launched this little TGM soiree. So, I claim disqualification by reason of competitive advantage. Or insanity. Take your pick!

And so it goes...

From the arena floor:

"We who are about to die salute you."

-- Gladiator's Salute :salut:

And from the grandstand: :occasion:

:laughing9

I want to proceed further mainly to get these never talked about relationships down and ill post a picture at some point to clarify things.

Now the next question is how do we plug the hinge action accumulator3 motion into our previous equation relating to the plane I discussed here.

Key

a = is the angle of the relationship between the where the plane I quoted above from when it directly goes into the ground plane (low point) vs where it actually is in degrees - relative to the angle this makes on the inclined plane.

b = This angle is the inclined plane going into the ground plane (this isn't exactly true but to elaborate would require more complication) at an angle. If you create a plane that vertically goes through both the ground and the inclined plane at 90 degrees of its intersection which is the plane line, you can find the angle on this plane

c = The hinge action plane off from the horizontal eg - Horizontal hinge action = 0 degrees and Vertical Hinge Action = 90 degrees

The equation is - ill write this like your doing it on a calculator

a divided by 90 times b minus c

Congrats you now know everything there is to know about the left arm in its own seperate compartment and its geometrical relations.

Now you can just mess around with the equations as you see fit - substituting this equation for the x variable on the last one....

Everyone will have to admit this is really cool stuff. This didn't come to me over night - I've just never had to put this into words before because I just visualise these, so I'm sorry if my explanations aren't perfectly clear.

Edit a and b where labeled wrong....

Booger Eater.

And all that time I thought choking the chicken was . . . uh nevermind.

The formulas you provided help clarify the roll aspect. Thanks again Mathew.

I can see it more clearly, but what would be great is if you could provide a couple of graphic examples.

On each graphic, pick any angle for #3 accumulator. Say 20 degrees at impact. Then show how wristcock and roll are calculated at the release point based on Jen's plane and the turned shoulder plane. Again, pick any reasonable angles.

Examples would help a bunch.


Bagger

Fog Alert
 

To simplify then,

a= the angle of the inclined plane relative to the ground plane
b= the difference between ? Jen's Plane at position 1 and Jen's plane at posiition 2?
c = The hinge action plane relative to horizontal or parallel


x=(a/90)*B-C

A labeled graphic would be very helpful

G2M

I accidently labeled a to mean b....

A graphic would be useful for both equations and will them soon....

The one that your not too sure on is the angle formed by the left arm plane vertical to the inclined plane relative to its low point position on the inclined plane (hence directly towards the ground plane)....

responding to your edit...

To simplify then,

B= the angle of the inclined plane relative to the ground plane
a= the difference between ? Jen's Plane at position 1 and Jen's plane at posiition 2?
c = The hinge action plane relative to horizontal or parallel


x=(a/90)*B-C

Understood
 

G2M,
I understand your post- thanks. So the edge of the front book cover and the back book cover edge, as they touch or run through the wall - whether at an angle or when both surfaces are parallel to each other- create lines on the vertical wall that are always parallel to each other- even when the plane of the covers are not- that is when the "up and down" angle of the planes are different for the two- they both still create parallel plane edges on the vertical wall. Now, if the plane angles are not the same "side to side" and they go through the vertical wall then those plane angle edges will not be parallel.

Now, could you make another post and just tell me what edge of the swing plane and what edge of the #3 accumulator plane are parallel? I'm afraid of looking back at all of the other posts-as I have a fear of fog! So don't worry if your answer is really simple- cause that's actually what I'm looking for.
Thanks,
Mike O.

The plane Mathew defined as Jen's plane starts out at the top as vertical/perpendicular to the swing plane. As the left arm moves down towards impact, Jen's plane rotates to a point near impact that is parallel to the SP. Picture the book again; if the spine is aligned with the left arm plane and one cover is aligned with the swing plane, place the other cover at 90* to the swing plane. Now mimic the movement of your left arm and wrist as you approach impact and allow the upward pointing book cover to rotate as though the book is closing. The closing cover will move to and through a position where the once upward point book cover is now parallel to the SP. I'm still working on the relationship with the #3acc/wrist cock. Still some fog there for me too. Maybe once the graphic is finished it will be clear to me. I have some thoughts on this but I'm still thinking.

G2M