Line of compression and tangential force - LynnBlakeGolf Forums

Line of compression and tangential force

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Old 04-02-2006, 03:03 PM
neil neil is offline
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Originally Posted by Mathew
I've been really trying to get into chapter 2 with in respects to physics to really get into Homer Kelley's mind further beyond than perhaps the text of the golfing machine itself and fully appreciate it.

It is my understanding (and ive just started studying this stuff so its very probable I've got the wrong end of the stick) that if you whirl a heavy object in a consistant orbit that the velocity and its mass (force) of the object being whirled around is always tangential to the point that the object is on the circle. Like if the string was cut - the ball would fly off at 90 degrees to the line of the centrifugal pull out.....

What is puzzling me is at impact the line of compression looks more down the angle of approach in picture 2-C-3 instead of down the tangent of the orbiting sweetspot. I would of thought the line of compression would be tangential to the orbit at the the point that the sweetspot travels through the ball.

Why also is in the picture 2-C-1, the line of compression pointing downwards at low point in comparison to the picture in 2-A?

Any ideas
Matthew.2-C-3 is the application of linear force for THE LOB SHOT using vertical hingeing and its associated clubface layback.In 2-C-1 the LOC is pointing down because the clubface is travelling downwards during the impact interval.In my opinion 2-A is showing a simple explanation of resilince without the additional confusion of the conditions shown thereafter.Remember LOC is not the line of flight.It may help to read 2-A.
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Old 04-02-2006, 04:01 PM
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Originally Posted by neil
Matthew.2-C-3 is the application of linear force for THE LOB SHOT using vertical hingeing and its associated clubface layback.In 2-C-1 the LOC is pointing down because the clubface is travelling downwards during the impact interval.In my opinion 2-A is showing a simple explanation of resilince without the additional confusion of the conditions shown thereafter.Remember LOC is not the line of flight.It may help to read 2-A.
Just one thing, I've read this book and the whole of chapter 2, which surprisingly also includes '2-A resilience' so much I can just about quote it all by memory. When someone says 'it may help to read 2-A' it really bugs the hell out of me...

I actually mean't 2-C-1#3.... it was accidental... I did not mean the lob shot pictures of 2-C-3....

I know the line of flight and the line of compression are seperate. You must take me to be a real idiot or something... That was not what I asked.....

My question is why is the clubhead force going down the angle of approach like in picture 2-C-1#3 instead of off a tangent of the circular clubhead orbit.
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Old 04-02-2006, 05:45 PM
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Burner Burner is offline
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Quote:

It is my understanding (and ive just started studying this stuff so its very probable I've got the wrong end of the stick) that if you whirl a heavy object in a consistant orbit that the velocity and its mass (force) of the object being whirled around is always tangential to the point that the object is on the circle. Like if the string was cut - the ball would fly off at 90 degrees to the line of the centrifugal pull out.....
If the string gets cut the ball flies out in a straight line directly away from the source of the centripetal force that is trying to pull it inwards.
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Old 04-02-2006, 07:32 PM
Golfie McG Golfie McG is offline
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Call the physics police
Originally Posted by Burner
If the string gets cut the ball flies out in a straight line directly away from the source of the centripetal force that is trying to pull it inwards.

No it does not.
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Old 04-02-2006, 09:10 PM
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Just my 2 cents, but I thought the reason Homer drew 2-C-1 #3 that way was to illustrate that both the angle of approach and the arc of approach methods of delivery will give a straight-away golf shot.

In ideal compression, the ball will not leave the clubface instantaneously, but after the ball has reshaped. Then the internal forces causes the ball to propel along the line of compression. (2-A)

The diagram illustrates why we have to hit the inside-quadrant to get a straight shot. The distance in the arc is the distance the clubhead will travel during the time the ball deforms and reforms. (In reality, that distance isn't very long, just exaggerated in the diagram to give room to see everything.)

BTW, have to check my physics books, but the circular motion of an object gives it a tangental and radial force. The combination is why an object will go in a circle and not either drive into the center or fly off in a tangent. When the circular force hits an independent object, the force calculation on the ball would be (the mass of the clubhead) X (tangential acceleration)
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Old 04-02-2006, 09:42 PM
Toolish Toolish is offline
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Originally Posted by rchang72
BTW, have to check my physics books, but the circular motion of an object gives it a tangental and radial force. The combination is why an object will go in a circle and not either drive into the center or fly off in a tangent. When the circular force hits an independent object, the force calculation on the ball would be (the mass of the clubhead) X (tangential acceleration)
A object travelling in a circle does NOT have tangential force.

Force gives acceleration. If it had tangential force it would go faster or slower around the circle.

Last edited by Toolish : 04-02-2006 at 11:00 PM.
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Old 04-02-2006, 10:52 PM
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Originally Posted by Toolish
A object travelling in a circle does NOT have radial force.

Force gives acceleration. If it had radial force it would go faster or slower around the circle.
Isn't centripetal force a radial force Probably should have said centripetal acceleration to be clearer. I think what you are describing is angular acceleration. But as I said, I'm at least 15 years from my last thoughts about physics.

Last edited by rchang72 : 04-02-2006 at 10:54 PM.
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Old 04-03-2006, 03:33 AM
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Originally Posted by Burner
If the string gets cut the ball flies out in a straight line directly away from the source of the centripetal force that is trying to pull it inwards.

From the website http://www.fearofphysics.com/BallString/ballstring.html

Look at the pictures here

Which way?






Quote:
The string exerts an inwards force on the ball, called the centripetal force. This is what keeps the ball flying in a circle. When the string is cut, this force vanishes (no more string, no more force). At this point there are no other forces acting on the ball (forget gravity for now). Why are forces so important? Because no object can change its direction unless a force acts on it (this is Newton's First Law).


Quote:
So what does the ball have after the string is cut? It still has its speed. The speed it had as it was rounding the circle just as the string was cut. This speed is pointing along the edge of the former circle (not outward along where the string used to be.) Without any forces, an object will always go in the direction of its speed (Newton's First Law again).
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Old 04-03-2006, 04:24 AM
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I think I have to look at this right from the beginning. I need to look at terminology, so im going to make sure I have these concepts and ill just paste them as I look them up to save anyone else interested the time...

- The line of compression is the direction of the impact force.
- Force is the capacity to do work or cause physical change; energy, strength, or active power.
- A Force is equal to mass times acceleration per newtons 2nd law
- Acceleration is the rate of change of velocity with respect to time.
- Velocity is a vector quantity whose magnitude is a body's speed and whose direction is the body's direction of motion.
- Vector is a quantity, completely specified by a magnitude and a direction.
- Magnitude is the greatness in significance.

Ok question time relating to these terms....

To maintain a certain velocity of anything, it is always accelerating ?

For a given force when a collision occurs, the force transfered by the acceleration really means the velocity created by that acceleration at that moment in time?

A ball whirling around like in my picture post above - since the velocity or acceleration (discounting the other forces just now) is always tangential to the orbit, then the force of that ball hitting anything (tangential force I assume) is also going to be tangential to its orbit?

and if this is true - then the direction of the clubhead force (keeping the clubface seperate for just now) traveling in its orbit should be tangential to the clubhead orbit?
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Old 04-03-2006, 07:21 AM
Toolish Toolish is offline
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Originally Posted by Mathew
I think I have to look at this right from the beginning. I need to look at terminology, so im going to make sure I have these concepts and ill just paste them as I look them up to save anyone else interested the time...

- The line of compression is the direction of the impact force.
- Force is the capacity to do work or cause physical change; energy, strength, or active power.
- A Force is equal to mass times acceleration per newtons 2nd law
- Acceleration is the rate of change of velocity with respect to time.
- Velocity is a vector quantity whose magnitude is a body's speed and whose direction is the body's direction of motion.
- Vector is a quantity, completely specified by a magnitude and a direction.
- Magnitude is the greatness in significance.

Ok question time relating to these terms....

To maintain a certain velocity of anything, it is always accelerating ?
No...a constant velocity means NO acceleration. Acceleration causes a change in velocity.

For a given force when a collision occurs, the force transfered by the acceleration really means the velocity created by that acceleration at that moment in time?
Force is not transferered by acceleration. Acceleration is created by force. Think of a golf ball dropped from height onto concrete to get an idea of force, accel and velocity. It is released from the hand and at that instant the only force on it becomes gravity (9.8m/s^2), so the ball accelerates down at approximately 9.8m/s^2 (disregarding drag through the air, as it is tiny in this instance), this acceleration continues until the ball hits the ground.

Assume the ball takes 1 second from the time it is released until the time it hits the ground, it will hit the ground at 9.8m/s (velocity). The ground then imparts a force on the ball, accelerating it in an upwards direction. This force and resultant acceleration stops the ball dropping. Due to ball compressing on contact with the ground, when the ball decompresses the upward acceleration continues and the ball ends up with an upward velocity (say m/s). Once impact with the ground is over and the ball is airborne again the only force is gravity and it all repeats


A ball whirling around like in my picture post above - since the velocity or acceleration VELOCITY AND ACCELERATION ARE NOT THE SAME(discounting the other forces just now) is always tangential to the orbitIntantaneous velocity is tangential to the orbit, but acceleration is towards the centre of the orbit. This acceleration is due to the force (tension) in the string, then the force of that ball hitting anything (tangential force I assume) is also going to be tangential to its orbit? The force of the ball hitting anything depends on what it hits and how. Assuming it hits a wall perpendicular to the balls orbit, then yes it will be a tangential force.

and if this is true - then the direction of the clubhead force (keeping the clubface seperate for just now) traveling in its orbit should be tangential to the clubhead orbit?I am confused as to waht you are asking here. The clubhead travelling in an orbit does not have force, it has velocity and momentum. Only once the club is contacts something (hopefully a ball) will it apply a force.
Hope that clears it up a bit?
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