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Originally Posted by smooth
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At seperation i.e. ball has left the clubface and hinge action has completed, i gather that the shaft lean will be different depending on the hinge action employed.
In one of the Yoda vids he mentions vertical hinging has the clubface laying back only, angled closing and laying back at the same time, and horizontal closing only
To have the clubface "laying back" wouldn't that also mean the shaft??
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That's right,
Smooth.
The Clubshaft will remain at all times in the plane of the
Left Arm Flying Wedge. This plane is the vertical plane of the Left Wristcock Motion.
Hinge Action -- the Flat Left Wrist held vertical (perpendicular) to one of the three Associated Planes (Horizontal, Angled or Vertical) -- will determine the amount of Clubhead Travel through Impact. Hence, it also determines the Clubshaft position during and at the end of the Follow-Through (the Both Arms Straight position).
As
Tongzilla has indicated above, the Clubhead (and, likewise, the Clubshaft) travels furthest when the Left Wrist is held vertical to the Horizontal Plane (Horizontal Hinging). Both travel shortest when the Wrist is held vertical to the Vertical Plane. Finally, they travel somewhere between the two when the Left Wrist is held vertical to the Angled Plane of the Stroke.
In TGM,
Rhythm is defined as maintaining the In-Line relationship of the Clubshaft and the Left Arm. Through Impact, that condition is maintained by the Flat Left Wrist executing its Hinge Action. Therefore, the answer to your question is...
The Clubshaft position is determined by the Rhythm of the Stroke (as determined by the Hinge Action employed).