Looks like to me the sweet spot is air born and only touches the point that defines its Plane Line once i.e. Low Point Plane Line. So since it's air born then there should be a line that extends from the sweet spot to the plane that it is adhering to?
If we are to accept 2-N-0 where the Sweet Spot Plane Line has been redefine (herein) to the Impact Plane Line which lies on the Sweet Spot Plane along with Low Point Plane Line, we discover that the Sweet Spot will pass through the Impact Plane Line (Plane Line) once on the down stroke and once on the up stroke, whereas it only passes through the Low Point Plane Line once.
In the event I misunderstood your post and it was to say I should extend a line downward...
I did just that when attempting to model it in real life.
What I discovered was that the 'roll' that the swinger employs during start up and initially in the backstroke does indeed pull the extended line (sweet spot plane) to the inside for Diagram 2. As for a hitter who doesn't employ an intentional roll, it stayed on line, Ah-Ha, oops in the initial modeling I used a fix point at the top of the club shaft(grip). When the fix point moved, then so did the line for diagram 2 again.
One simple way to prove or disprove the the diagrams, etc. is to use either a vertical or horizontal plane instead of an Inclined plane. By doing that it removes one component of the motion, either In (Vertical Plane) or the Up (Horizontal Plane). Basically making this a 2 dimensional model initially, removes complexit. Then add back in the 3rd dimension by using an Inclined Plane.
Thought I would add my response to a similar thread on Brian's site re: sweetspot and hosel rotation
Take a club and hold it in your thumb and forefinger at the very end of the grip.
Spin it around (or better, imagine you could spin it fast)
(as noted by shootin4par on Brian's site, you can hold it between your palms to do this)
Notice that because of the design of the club, the clubhead spinning in this way travels in a 'circle' - from the tip of the grip end where you are holding it - to the 'center' of the circle create when you spin the club in this way.
The 'center' of that circle is, in effect, the sweetspot
Now - imagine this same picture - but in a horizontal plane....
then in a golf motion....
The hosel (or if it helps to picture it, the shaft) rotates around that 'circle'
__________________
"Support the On Plane Swinging Force in Balance"
"we have no friends, we have no enemies, we have only teachers"
Simplicity buffs, see 5-0, 1-L, 2-0 A and B 10-2-B, 4-D, 6B-1D, 6-B-3-0-1, 6-C-1, 6-E-2
For all the responses and I understand what has been said, BUT it is clear I am either missing a major factor here or ....
If the Clubshaft is to remain FLAT against the Inclined Plane having a Straight Plane Line and the Sweet Spot Plane Line is also straight you can if you rotate at the correct rate, one and only rate to maintain those relationships.
Since Hitters and Swingers 'Swivel' in the Back Stroke at different rates makes this impossible to maintain the above relationships UNLESS the back stroke speed of a hitter and swinger must be different, the hitter having the slower back stroke.
Also if we could easily quanitify this rotation rate per back stroke speed, we could provide a key for a golfer to remain On Plane,.
As for the Down Stroke, same problem exists.
And none of this accounts for LAG or Droop which will again affect the outcome.
One thing we all should be able to walk away from this discussion is that you DON'T want to monitor the Club Head, you DON'T want too focus on the Club Head. It has to be the HANDS else the uniqueness of the stroke will be very open to inconsistencies and create a number of TGM 'X' Components.
It would be an interesting study to see how different the time it takes to make a SWING vs. Hit is, and if there is a correlation. The Tour Tempo method for this might be good.
So when the hands are turned or rolled onto the plane the shaft should point at the ball, and when they aren't the shaft should point just inside the ball. Yes? No?