10-11-0-3 Quarter Turn of #3 PP and The First Knuckle and back again??? - LynnBlakeGolf Forums

10-11-0-3 Quarter Turn of #3 PP and The First Knuckle and back again???

Emergency Room - Swingers

Reply
 
Thread Tools Display Modes
  #1  
Old 12-11-2006, 11:57 AM
Mathew's Avatar
Mathew Mathew is offline
Inactive User
 
Join Date: Jan 2005
Posts: 833
Originally Posted by 12 piece bucket
OK I'm now smellin' you loud and clear . . . . it has to do with the selected Wrist Action then right? As a result of the left palm facing the Plane (Standard Wrist Action) the Load HAS TO move to the Knuckle . . . where as if your Left Wrist stayed Vertical to the Plane it would Load on the pad where Mr. K defined the #3 Pressure Point.

QUESTION on the second part . . . B-Variation . . . at what point would you start to feel it move from the knuckle back to the pad? When the #3 is actuated?

Appreciate you bearing with me man!

Thanks for the clarification boss . . . Good stuff!
Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....

Last edited by Mathew : 12-11-2006 at 12:01 PM.
Reply With Quote
  #2  
Old 12-11-2006, 12:23 PM
12 piece bucket's Avatar
12 piece bucket 12 piece bucket is offline
Senior Member
 
Join Date: Jan 2005
Location: Thomasville, NC
Posts: 4,380
Originally Posted by Mathew
Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....
Thanks man! You have made an integral contribution to my understanding of this stuff . . . Thanks for your help!
__________________
Aloha Mr. Hand

Behold my hands; reach hither thy hand
Reply With Quote
  #3  
Old 12-11-2006, 12:51 PM
Mathew's Avatar
Mathew Mathew is offline
Inactive User
 
Join Date: Jan 2005
Posts: 833
Originally Posted by 12 piece bucket
Thanks man! You have made an integral contribution to my understanding of this stuff . . . Thanks for your help!
Nae Probs
Reply With Quote
  #4  
Old 12-11-2006, 05:11 PM
golfbulldog golfbulldog is offline
Senior Member
 
Join Date: Dec 2005
Posts: 647
the complete swingers jigsaw puzzle...
To swing the way that Matthew describes you need all the swingers components ( or jigsaw pieces)... standard wrist action leads to right forearm position supporting loading of 2ndry lever (right elbow pointing more down)...leads to quarter turn rotation of PP3.... leads to pitch elbow (more readily)... etc

If you swing but use single wrist action then you get no quarter turn PP3 loading etc...still swinging because drag loading but using a component more typical of hitting and simultaneous release... all other swingers components can then be added but it is not as pure swing...

I am sure that Comdpa has written somewhere about the type of hinge action being determined in the backswing... it seems that the more turn to plane occuring in the backswing the more readily one horizontal hinges in the impact interval region.... and vica versa...

Just a few thoughts... shoot it down if you think i got it wrong ... looking to learn! Thanks
Reply With Quote
  #5  
Old 12-12-2006, 12:39 PM
EdZ EdZ is offline
Lynn Blake Certified Instructor
 
Join Date: Jan 2005
Location: West Linn, OR
Posts: 1,645
Originally Posted by Mathew
Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....
Nice post Mathew - the 'wheel rim' -
__________________
"Support the On Plane Swinging Force in Balance"

"we have no friends, we have no enemies, we have only teachers"

Simplicity buffs, see 5-0, 1-L, 2-0 A and B 10-2-B, 4-D, 6B-1D, 6-B-3-0-1, 6-C-1, 6-E-2
Reply With Quote
Reply


Thread Tools
Display Modes

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

vB code is On
Smilies are On
[IMG] code is On
HTML code is Off
Forum Jump


All times are GMT -4. The time now is 07:39 AM.


Design by Vjacheslav Trushkin, color scheme by ColorizeIt!.