"sweet spot" physics- where are you? - LynnBlakeGolf Forums

"sweet spot" physics- where are you?

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Old 12-07-2011, 08:59 AM
HungryBear HungryBear is offline
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Originally Posted by Daryl View Post
The Golf Club has various balance points and the Clubhead also has a balance point (COG). The #3 PP senses and directs the Clubhead COG.

The Clubhead COG has an Orbital Path. The Ball has a COG.

It's important to note that the COG of the Ball always intersects the COG Orbit of the Clubhead unless you're hitting a specialty shot (i.e. Driver off the deck or sand shot).





Please note that the Impact and Separation points are for illustrative purposes only. Although Impact and separation points may be the same on the Horizontal Plane, it isn't necessary (or even possible, except during Vertical Hinging) on the Vertical Plane.

MY BOLD of quote;

Senses NO, Directs YES;
Lacking demonstrable knowledge of the Mechanical Dynamics. I start at the place that the "sweet spot" is a learned POSITION and is located by YOUR COMPUTER in a mechanical manner. Now, IF mechanical dynamics (physics) of the "sweet spot" (lets use Centroid or center of mass) can demonstrate a "sensable" effect we have something new. I have not found that effect.

HB

Last edited by HungryBear : 12-07-2011 at 09:19 AM.
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Old 12-07-2011, 01:00 PM
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BerntR BerntR is offline
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I recently learned about Center of Percussion.

It's the impact point where there will be no shock transmitted to the hands. This seems to be considered the sweet spot in baseball batting. And it is most certainly the sweet spot for a hammer.

Not that if impact happens below the COP, a forward force would be generated at the hinge pin. I guess that corresponds with the harsh feel of flipping and topping at the same time.



Then you have the Center of Oscillation. I often call this the Moment Of Inertia Center, but that term seems to not be used in English. Anyway, this is the inertia center as seen from the hinge. When the stick becomes a pendulum around the hinge, there will be as much velocity energy below this center as above it.Radius of gyration is the distance from the hinge to the Center of Oscillation so these two terms are often interchanged. For a clubhead with a given mass, the radius of gyration will correlate with how hard it is to swing the club. more radius of gyration means more inertia.

Until recently I thought this center had the same property as the center of percussion, but it doesn't. It sits higher on the stick. It will always be somewhere between the COG and the COP in the figure above.

Center of Gravity is the last term in the club.

Here's a patent dealing with how to get the COP in the center of the club head:http://www.ptodirect.com/Patents/5629475

This indicates that the COP is the true sweet spot. But perhaps there's more to it than just where the COP is.
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Old 12-08-2011, 03:45 PM
HungryBear HungryBear is offline
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coordinate system
First lets pick a coordinate system. Since this is going to be "hand waveing" rather than math lets us a Cartesian system - X, Y, Z. the "plane of the swing" defined as X,Y and any above or below plane defined a Z. A cylindrical system may be more appropriate but harder to understand. and polar system would become impossible. So the swing plane is a flat X,Y plane and deviation above or below this plane is +/- Z. (Just geting started) Any engineers object?

hb
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Old 12-09-2011, 10:20 AM
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I'm curious to see where you're going with this, hb.
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Old 12-09-2011, 12:22 PM
HungryBear HungryBear is offline
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Using a "test club" with the tip weighted to equiv. of club head mass and swinging this "club" flat on yhe X,Y plane , about the Z axis , with a "MACHINE" that either pulls or pushes as the TGM power package. The shaft will remain flat on the plane and the tip will either LAG or LEAD dependent on if it is accelerating or decelerating. (shaft will flex)this is due to tangential acceleration. And, there will be a SUBSTANTIAL radial force due to the radial acceleration.(shaft trys to stretch) A sensor located about where #3 would be can be used to sense the tangential acceleration but not the radial acceleration. AND the position of the TIP is unknown until PRACTICE has adapted the machine computer to compensate for variables. ie. the club becomes part of the machine. like any tool we use. pen, fork keyboard. sword etc. we just practice into automatic.

OK so far?

hb

HB
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Old 12-10-2011, 11:30 AM
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Daryl Daryl is offline
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"Radial" and "Longitudinal" reference (TGM) the Pressure Point (Senses and Directs) Alignment with the Clubface at Release (Pulley). "Radial" is termed to describe the PP at Right Angles to the Clubface and "Longitudinal" is termed to describe the PP which is Parallel to the Clubface.

The Pivot, Power Package and Pulley all contribute to Angular Acceleration regardless of Hitting or Swinging. The term "Throwout" is used to describe the Clubhead being moved around the Pulley by Centrifugal Force (Radial Acceleration) while "Driveout" is used to describe muscular effort propelling the Clubhead around the Pulley (same Radial Acceleration). Regardless of Method, it is the "Pulley" that creates Clubhead Acceleration and not the type of Thrust or how the PP is Aligned to the Clubface.
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Old 12-10-2011, 04:59 PM
HungryBear HungryBear is offline
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Physics term.
Daryl, we are speaking physics. I am slowly developing the physics of the "sweet spot" . At this point I have not assembled the club only a "test club" . Radial is a vector from the center -Z axis as defined and tangential is in the X,Y plane at a constant redius from Z=0, X=0, Y=0.
If you have the Physics of the "sweet spot" please contribute.

#3 pp is, as the word is. a POINT. with dimension. only sensing one dimension. The radial sensing is apparently accomplished within the "checkrein" response an I find no specific ref. in TGM to this sensor

HB

Last edited by HungryBear : 12-10-2011 at 05:35 PM.
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