Save me here guys,
Do you agree that the clubshaft is on plane ,and as the secondary lever assembly and one side of the#3 acc angle it sits on both planes?
Neil,
That's how I see it. Matthew's still has lost me - but with a little work I think we'll get there.
Put your book against a wall so that when the book is open the books contents are facing the wall. As the two covers extend on to infinity and cut through this wall the lines of intersection will be parallel.
...
Mr. Kelley - I mean Mathew
One thing at a time- call me stupid or maybe I just have a communication problem with engineers or similar type folks. So how does your quote above differ from my explanation of parallel.
Let me guess:
In your example, the wall is vertical and the spine is closest to me- and the book is spread open- so the front cover is say angled 45 degrees toward the sky and the back cover is aimed 45 degrees towards the ground - and both are going through the wall at the same angle but different directions? And that's parallel? Just guide me through this example if I missed it- and be very clear so that I can visualize what your describing.
Anotherwords, was my definition of each point opposite from the the other plane - being the same distance not correct? Are we talking the plane surfaces parallel or the plane lines parallel or the plane edges parallel- still need help.
Thanks,
Mike
"what I see is the red plane representing the perpendicular(to the plane of the left arm assembly) plane of the left wrist hinge pin, so the motion would be horizontal/parallel to the inclined plae of the left arm assembly until the swivel starts, and then the red plane would have to rotate to the finish position."
I'm still not sure what it means in terms of the golf swing, but I think I finally got it. First off, Jen's plane exists at all positions through the swing. As matthew has defined at at the top, it is vertical to the inclined plane. The orientation of Jen's plane relative to the inclined plane however is different at each position you look at through the swing. It's is just a representation of the rotation through impact of the left wrist hinge pin. At the top, it would be vertical, at impact parallel, and at finish, vertial again. This is Matthew's closing book analogy. Also, since the cocking/uncocking motion of the #3acc stays in the plane of the left arm, I can't see how Jen's plane is affected by the amount of wristcock at any particular position.
Mr. Kelley - I mean Mathew
One thing at a time- call me stupid or maybe I just have a communication problem with engineers or similar type folks. So how does your quote above differ from my explanation of parallel.
Let me guess:
In your example, the wall is vertical and the spine is closest to me- and the book is spread open- so the front cover is say angled 45 degrees toward the sky and the back cover is aimed 45 degrees towards the ground - and both are going through the wall at the same angle but different directions? And that's parallel? Just guide me through this example if I missed it- and be very clear so that I can visualize what your describing.
Thanks,
Mike
Mike; "Lines of Intersection" (with the wall). Of course these will be parallel. Any two lines, starting parallel to one another(the book edges), when extended to infinity, their lines of intersection with a common plane (the wall) will also be parallel.
In your example, you are thinking of the surface plane of the book cover, not the line or edge of the plane When the plane of book cover 1 and the plane of book cover 2 intersect a common plane, like the wall, each transcribes a line. These two intersections will be parallel to one another, even though the direction of the two book covers approaching the plane (wall). Try it for your self. Take a hard v=cover book and hold it against a solid surface that you can write on. Hold the book open to the amount of your choice and while hilding it in that position, trace the edge of the book cover where it touches the hard surface. Try it several times, at different amounts of open or closed. The tracings will always be parallel.
G2M
Last edited by golf2much : 08-31-2006 at 11:25 AM.
I don't have 3D drawing tools, but it's not too difficult to visualize the motion.
Matthew, please make comments/corrections to my crude drawing. The red/yellow planes merge/unmerge, and rotate together throughout the swing, but always stay in the plane of the left wristock motion.
In the golfers model, there isn't any useful relation to the inclined plane because of the variance of motion in the left arm. I'm still waiting for that ah ha moment though.
OK Matthew, I think we're getting pretty close to the mechanics of what you are trying to say with wordy descriptions and baggers drawings, but like bagger, the ah-ha moment continues to escape me. Maybe you could give us a bit more insight as to why this new plane is significant.
OK Matthew, I think we're getting pretty close to the mechanics of what you are trying to say with wordy descriptions and baggers drawings, but like bagger, the ah-ha moment continues to escape me. Maybe you could give us a bit more insight as to why this new plane is significant.
G2M
Fair question Matthew. Would you explain the importance of understanding this information?
I don't have 3D drawing tools, but it's not too difficult to visualize the motion.
Matthew, please make comments/corrections to my crude drawing. The red/yellow planes merge/unmerge, and rotate together throughout the swing, but always stay in the plane of the left wristock motion.
In the golfers model, there isn't any useful relation to the inclined plane because of the variance of motion in the left arm. I'm still waiting for that ah ha moment though.
Bagger
The plane of the left wristcock motion (same as acc no.3 plane) per the flying wedges is a left arm plane. The sweetspot stays in this plane. The left arm nor the left flying wedge sits flat on the inclined plane. It comes from above the inclined plane.
When the hand is not turned towards the plane (which I thought would make the relationships pretty clear...) and is anywhere else - the LCOG will lay on the inclined plane on the angle that accumulator 3 plane makes as it passes through it. The wristcock no of degrees can then be determined by the angle between that line of intersection just described and the angle it makes with relation to Jens plane.
Linear Mode
