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Old 09-02-2006, 03:18 PM
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golf2much golf2much is offline
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Join Date: Jan 2005
Location: Tampa Florida Area
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Mathew
Originally Posted by Mathew
Well lets see all this stuff in action...

Ok lets say the left arm is 30 degrees from low point - we are using Horizontal Hinge action, and the plane angle is 30 degrees

ok so then we can input this into our equation

30 divided by 90 is 0.3333... or 1/3 of 30 so that is 10 degrees accumulator 3 has turned from vertically going through the inclined plane.

Now lets find out the amount of wristcock for the 10 degrees accumulator no.3 and lets just say the left arm is 5 degrees above plane

so pluging this into the first equation

10=y-((10/90)times 5))
10=y-0.555555...
lets rearrange this a little
y=10+0.555555...

So the wristcock is 10.55555...

Magical huh
I thought the point of the exercise was to be able to calculate the wrist cock position, or maybe to measure the release. If you have to assume that the left are is "say 5* below plane" to calculate the wristcock, what is the point. I appreciate the mathematics, and I'm sure the math is right, but for this approach to have value, you should be able to calculate the degree of below plane of the laft arm, and in turn the wristcock. I think I can picture how you would do this, but I'm interested in your thoughts.

Also, as a "real world" issue, what do you think is the significance of being able to calculate the exact degree of wrist cock, or is this just a test question in the making? Another real world issue, is that you would have to put a golfer in a pretty precise and golfer to golfer consistent photo set up to be able to even analyze these issues with any reliability. And finally, other than helping us understand the relationships between the components how would you impart this knowledge as an instructor?

G2M
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