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Old 03-19-2009, 02:45 PM
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Join Date: Jan 2005
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Force Feed
Originally Posted by BBax View Post
Just if your interested:

Where Vfict (r) is the potential responsible for the
centrifugal force: fc = −ω×(ω×r) = (ω2−ω ωT)r
.
Vfict (r) = −1
2 rT(ω2 − ω ωT)r
Now, Rs and RJ are parallel and MsRs+MJRJ =
0.
[Note that if a particle is moving then addi-
tional Coriolis forces act that are not mentioned
in @
@rVeff (r), so we can’t determine stability from
Veff .

Any questions?
Yes Rob, are you sure that your calculation 2 rT(ω2 − ω ωT)r should not be 1.8 rT(ω2 − ω ωT)r ? Just wondering.
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