10-11-0-3 Quarter Turn of #3 PP and The First Knuckle and back again???

[12 piece bucket]

It has nothing to do with the assembly point except that you must assemble the accumulators you wish to use per stroke pattern at some point. As soon as you swivel and bring those hands flat to the plane and start loading the secondary lever assembly that loading action puts the pressure onto the first knuckle. That becomes the pressure you move onplane per my last post. Just like the swinger has a sequenced release - it should also be somewhat more of a sequenced loading... It is the fact that the swinger will swivel somewhat quicker to the plane than the hitter, the motion of no.2 creates the pressure against the first knuckle.

You can then just try to keep the longitudinal onplane pressure and not try to change it until centrifugal force whirls out the secondary lever assembly (A-variation grip) or you can maintain the pressure all the way down by allowing it to rotate back with the acc no.3 (B-Variation grip)....

OK I'm now smellin' you loud and clear . . . . it has to do with the selected Wrist Action then right? As a result of the left palm facing the Plane (Standard Wrist Action) the Load HAS TO move to the Knuckle . . . where as if your Left Wrist stayed Vertical to the Plane it would Load on the pad where Mr. K defined the #3 Pressure Point.

QUESTION on the second part . . . B-Variation . . . at what point would you start to feel it move from the knuckle back to the pad? When the #3 is actuated?

Appreciate you bearing with me man!

Thanks for the clarification boss . . . Good stuff!

[Mathew]

OK I'm now smellin' you loud and clear . . . . it has to do with the selected Wrist Action then right? As a result of the left palm facing the Plane (Standard Wrist Action) the Load HAS TO move to the Knuckle . . . where as if your Left Wrist stayed Vertical to the Plane it would Load on the pad where Mr. K defined the #3 Pressure Point.

QUESTION on the second part . . . B-Variation . . . at what point would you start to feel it move from the knuckle back to the pad? When the #3 is actuated?

Appreciate you bearing with me man!

Thanks for the clarification boss . . . Good stuff!

Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....

[12 piece bucket]

Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....

Thanks man! You have made an integral contribution to my understanding of this stuff . . . Thanks for your help!

[Mathew]

Thanks man! You have made an integral contribution to my understanding of this stuff . . . Thanks for your help!

Nae Probs

[golfbulldog]

To swing the way that Matthew describes you need all the swingers components ( or jigsaw pieces)... standard wrist action leads to right forearm position supporting loading of 2ndry lever (right elbow pointing more down)...leads to quarter turn rotation of PP3.... leads to pitch elbow (more readily)... etc

If you swing but use single wrist action then you get no quarter turn PP3 loading etc...still swinging because drag loading but using a component more typical of hitting and simultaneous release... all other swingers components can then be added but it is not as pure swing...

I am sure that Comdpa has written somewhere about the type of hinge action being determined in the backswing... it seems that the more turn to plane occuring in the backswing the more readily one horizontal hinges in the impact interval region.... and vica versa...

Just a few thoughts... shoot it down if you think i got it wrong ... looking to learn! Thanks

[EdZ]

Yup, at least thats the way I see it...

As soon as the hands turn to the plane for the swinger, the wristcock is put onplane - pp2 and the rotated pp3 have a symbient relationship because they both then travel around the same circle made by the secondary lever assembly.

It is all about the law of the flail per 2-K. For the longest time I thought I understood this but you have to remember that the wrist conditions with the hands are relative to the clubshaft and the inclined plane, not to the arms when dealing with the onplane flail. It is a recent understanding of mine that whilst the wrist conditions at the top are written as Flat, Cocked, and Turned for the left hand... you have to remember that flat is flat to the inclined plane and will therefore bent in relation to the left arm to the exact degree that the left arm is above the plane... this allows the onplane loading to be purely of acc no.2 when turned to the plane. The right wrist is Level, Bent and Turned also to the inclined plane. Since the right hand is onplane - the hand is level to the LCOG (irregardless of right forearm position - which per the flying wedges has a relationship with acc no.3 not no.2), Bent to its impact fix degree.... therefore as the left wrist cocking motion is onplane and the secondary lever assembly's motion is onplane - as the right hand stays level to that club, the pressure will always be at 90 degrees onplane to the LCOG around the interior circle of the hands (our right hand lower than the left) as the left wrist cocks.....

Nice post Mathew - the 'wheel rim' -

[golfbulldog]

QUESTION on the second part . . . B-Variation . . . at what point would you start to feel it move from the knuckle back to the pad? When the #3 is actuated?

Appreciate you bearing with me man!

Thanks for the clarification boss . . . Good stuff!

Rotating pressure point link - love this!

http://www.lynnblakegolf.com/gallery... 9999&way=asc

This is a key topic for my swinging understanding and i apologise for the review. BUT i have a few questions please...

On the downswing when the lag pressure is experienced on the rotated pp3 ( knuckle) - are the hosel, sweetspot and shaft all on the same plane?

My understanding is yes.

With standard wrist action ( as per Buckets question above) there will be rotation of hosel and shaft around the sweet spot - thus seperating the planes. With automatic release, does this occur when Accumulator 2 releases... left wrist reaches level and starts the roll of accumulator 3?

My understanding is yes... and with strong single action grip... pp3 starts to rotate to fleshy part of index finger pad ( i love the Hogan Homevideo in Yoda Gallery - hope this link works:-

http://www.lynnblakegolf.com/gallery... 9999&way=asc

where he shows this!!! I mean love!!! To see and hear him talk about pp3... thanks for the clip,Yoda)

We do not want to lag the hosel into impact but i guess we do ( with grip variation B(strong single action)) want to lag the hosel up until release point - yes? no?

What happens if you start the downswing ok ( not casting) and club is maintained turned to the plane... but you start to lose lag pressure...

...presumably the heavy toe of the club drags the clubface more open, shaft and sweetspot plane control is lost ( under plane)... and the only way to square to impact is flip or mega pivot?? If you don't square it up then shanks occur because youare still lagging ( to a small degree) the hosel??

Maybe??

Thanks for your thought.